Question

Prove that : (x+y × x-y) + (y+z×y-z )+ (z+x ×z-x) =0​

Answer 1

Answer:

Step-by-step explanation:by a^2-b^2 formula were a^2-b^2=(a-b)(a+b)

thn (x^2-y^2)+(y^2-z^2)+(z^2-x^2)

opposite signs get cancelled and hence 0.

Answer 2

Answer:

multiply first all the terms that are in the bracket and then u need to do sum of all teh terms there u will see that all teh terms got cancelled out

so the given statement was proved