Math, asked by AKSHAY8127G, 10 months ago

prove that(x-y)(x+y)+(y-z)(y+z)+(z-x)(z+x)=0​

Answers

Answered by itssakshi94
12
Hope you understand this and it helps you
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Answered by Anonymous
7

Answer:

To proof -

(x-y)(x+y)+(y-z)(y+z)+(z-x)(z+x)=0

x² - y² + y² - z² + z² - x² = 0

0 = 0

Hence Proved

(x-y)(x+y)+(y-z)(y+z)+(z-x)(z+x)=0

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