Question

prove that (x+ y)(x-y)+(y+z)(y-z)+(z+x)(z-x) = 0​

Answer 1

Answer:

w.k.t

(x+y)(x-y-)=x^2-y^2

x^2-y^2+y^2-z^2+z^2-x^2=0

ALL WILL GET CANCEL

Step-by-step explanation:

0=0

Answer 2

$(x + y) +( x - y) + (y + z)(y - z) \\ + (z + x)(z - x) = 0\\ Or,{x}^{2} - {y}^{2} + {y}^{2} - {z}^{2} + {z}^{2} - {x}^{2} = 0 \\ Or , 0 =0\: \: (proved)$

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