Question

Prove that (x-y) (x+y) + (y-z) (y+z) + (z−x) (z+x) = 0.​

Answer 1

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

Prove that (x-y) (x+y) + (y-z) (y+z) + (z−x) (z+x) = 0.

(x-y) (x+y) + (y-z) (y+z) + (z−x) (z+x) = 0.

a² - b²

(x² - y² ) + ( y² - z² ) + ( z² - x²) = 0

x² - y² + y² - z² + z² - x² = 0

0 = 0

LHS = RHS

Hence proved

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