Question

Prove that (x-y)(x+y)+(y-z)(y+z)+(z-x)(z+x) = 0​

Answer 1

Answer:

they all are veriabal so there were no numerical number so the answer is 0 only

Step-by-step explanation:

but if we do this some I have also the solution

Given that,

xy(x−y)+yz(y−z)+zx(z−x)

=(x×x×y)−(x×y×y)+(y×y×z)−(y×z×z)+(z×z×x)−(z×x×x)

→x

2

y−xy

2

+y

2

z−yz

2

+z

2

x−zx

2

pls mark me brilliant