prove that (x-y)(x+y)+(z+x)(z-x)=(z+y)(z-y).
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Step-by-step explanation:
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Answered by
1
Step-by-step explanation:
Lhs=(x-y) (x+y) +(z+x) (z-x)
=x(x-y) - y(x+y) +z(z-x) +x(z-x)
=x^2-y^2+z^2-x^2
=z^2-y^2
=(z+y) (z-y)
=rhs
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