Prove that x2+6x+15 has no zero.
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Let f(x)=x²+6x+15
For every existing zeroes the function has to be equal to 0.
when, f(x)=0,
x²+6x+15=0
=>x=(-6±√(36-60))/2=(-6±i√24)/2
The function has zeroes only in complex numbers. But for real numbers it has no zeroes. [Proven]
For every existing zeroes the function has to be equal to 0.
when, f(x)=0,
x²+6x+15=0
=>x=(-6±√(36-60))/2=(-6±i√24)/2
The function has zeroes only in complex numbers. But for real numbers it has no zeroes. [Proven]
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