Question

Prove that x²+6x+15 has no zero.
Please anyone answer!!!
Please

Answer 1

Hey there !!!!

If a quadratic polynomial is of the form ax²+bx+c=0

Then if discriminant i.e, b²-4ac<0 then polynomial has no real roots.

If b²-4ac>0 polynomial has real and distinct roots.

If b²-4ac=0 roots are real and equal.

So, x²+6x+15 has no roots then b²-4ac<0

here a=1 b=6 c=15

                =6²-4*1*15

                 = 36-60<0

Discriminant of x²+6x+15 is less than 0 so given equation has no real roots.

Hope this helped you.....

Answer 2

a=1, b=6 , c= 15

Discriminant = b^2 - 4ac

D= (6)^2 -4×1×15
D= 36- 60
D= -24

if D is less than zero then the equation has no real roots( D is negative).

hence this quadratic equation has no root