Question

prove that xa[b-c]/xb[a-c]/[xb/xa]c=1

Answer 1

x^a(b - c) / x^b(a - c) ÷ (x^b/x^a)^c 
= [x^(ab - ac) / x^(ab - bc)] ÷ x^(bc) / x^(ac) 
= x^-2ac 

= 1
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Answer 2

Answer:

x^a(b - c) / x^b(a - c) ÷ (x^b/x^a)^c  

= [x^(ab - ac) / x^(ab - bc)] ÷ x^(bc) / x^(ac)  

= x^-2ac  

= 1

I hope this answers help you

please make this answers brainliest