Question

prove that [ xa²/xb²] 1/a+b x [xb²/xc²] 1/b+c x [ xc²/xa²] 1/c+a = 1 please open n send ​

Answer 1

Answer:

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Step-by-step explanation:

L .H .S

(Xa/x-b)a-b . (xb/x-c)b-c .(xc/x-a)c-a

= (xa+b)a-b , (xb+c)b-c .(xc+a)c-a

= x(a+b)(a-b) . x(b+c)(b-c) .x(c+a)(c-a)

= xo

= 1 = R.H.S.

Answer 2

Answer:

Hence proved L.H.S =R.H.S

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