Prove that (xb-c)a. (xc-a)b.(xa-b)c= 1
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Answered by
2
Answer:
x
a−b
)
a+b
(x
b−c
)
b+c
(x
c−a
)
c+a
x
a
2
−b
2
x
b
2
−c
2
x
c
2
−a
2
=x
a
2
−b
2
+b
2
−c
2
+c
2
−a
2
=x
0
=1=RHS
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Answered by
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