Question

prove that y axis is the tangent of the circle x^2+y^2+6x-10y+25=0​

Answer 1

Step-by-step explanation:

x² + y² + 6x - 10y + 25 = 0

x² + 6x + y² - 10y + 25 = 0

x² + 2*3*x + 3² - 3² + y² - 2*5*y + 5² - 5² + 25 = 0

<in the above step we have added 3² and subtracted 3² So total, + 3² - 3² = 0. Similarly for '5'>

(x² + 2*3*x + 3²) + (y² - 2*5*y + 5²) - 3² - 5² + 25 = 0

(x + 3)² + (y - 5)² - 9 - 25 + 25 = 0

(x + 3)² + (y - 5)² - 9 = 0 __________(i)

This is the equation of circle.

The equation of Y-axis is x = 0.

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May you solve the rest...!?

Thanks!