Math, asked by samriddhachandra14, 1 year ago

prove that:

(y + z – x)3 + (z + x - y)3+ (x + y - z)3
=-24xyz​

Answers

Answered by MrPõisoñ
0

Observe that,

(x+y+z)3−(x+y−z)3=2z((x+y+z)2+(x+y−z)2)+(x+y)2−z2)=2z(3(x+y)2+z2)(1)

and,

(x−y−z)3−(x−y+z)3=−2z((x−y−z)2+(x−y+z)2)+(x−y)2−z2)=2z(3(x−y)2+z2)(2)

Therefore,

(x+y+z)3+(x−y−z)3−(x−y+z)3−(x+y−z)3=((x+y+z)3−(x+y−z)3)+((x−y−z)3−(x−y+z)3)=2z(3(x+y)2+z2)−2z(3(x−y)2+z2)=2z(3⋅4xy)=24xy

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