Question

prove that:-|z|=0 if and only z=0​

Answer 1

Step-by-step explanation:

let z= x+iy

then |z|=√(x^2+y^2)

if |z|=0

then √(x^2+y^2)=0

x^2+y^2=0

here x^2 and y^2 cannot equal to be negative number because square of any positive or negative number be only positive number then the sum of two positive numbers cannot equal to zero

it will possible when x and y values are equal to zero

so x=0 and y=0

then z= (0)+i(0)=0

z=0

hence proved