Math, asked by azharudheenmohammed0, 1 day ago

prove that (z1+z2)³=z1³+3z1²z2+3z1z2²+z2³

Answers

Answered by flower20282033

1

Answer:

(z1+z2)³=z1³+3z1²z2+3z1z2²+z2³

Step-by-step explanation:

(z1+z2)³=(z1+z2)^2 (z1+z2)

=(z1²+z2²+2z1z2) (z1+z2)

=z1³+3z1²z2+3z1z2²+z2³

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