Question

Prove that zero upon zero = 2

Answer 1

Answer:

Step-by-step explanation:

Actually $\frac{0}{0}$ is undefined

we can show $\frac{0}{0} = 2$ while taking some deviations

$\frac {0}{0} = \frac{x^2-x^2}{x^2-x^2}$

Using   a² - b² = (a+b)(a-b)

=> $\frac {0}{0} = \frac{(x+x)(x-x)}{x(x-x)}$

Now cancelling (x-x) from numerator & denominator (actually cancelling (x-x) is not allowed as x-x = 0 and cancellation of zero not allowed

=> $\frac{0}{0} = \frac{(2x)}{x)}$

=> $\frac{0}{0} = 2$

Hence Proved ( which is actually wrong)