Question

Prove that2
$2\sqrt{3} \div 5$
is an irrational number.​

Answer 1

Answer:

$let \: \\ \: \frac{2 \sqrt{3} }{5} be \: \: a \: rational \: no \\ so \: \\ \frac{2 \sqrt{3} }{5} = \frac{a}{b} \\ \sqrt{3} = \frac{5a}{2b} \\ now \: we \: have \: at \: lhs \: a \: irraional \: no \\ and \: at \: rhs \: a \: rational \: no \: \\ this \: due \: to \: our \: wrong \: assumption \\ \\ \frac{2 \sqrt{3} }{5} is \: an \: irrational \: no$

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