Math, asked by priyakchauhan97226, 9 months ago

prove that7✓5 is an irrational number.​

Answers

Answered by pranavlsgreat210120
5

Let 7√5 be rational.

So,

7√5 =

 \frac{p}{q}

where p and q are coprimes and integers and q is not equal to 0.

√5 = p/7q

RHS is rational but LHS is irrational.

Rational cannot be equal to irrational.

Hence, assumption is contradicted.

7√5 is irrational.

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Answered by sonalmvalia
3

Answer:

Let 7√5 be a rational number.

So,

7√5 = p/q.

(p and q are co-prime number and q ≠ 0)

=> √5 = p/7q

As, we can see that p/7q ia rational so √5 should also be rational. But this contradict the fact that √5 is irrational.

So, by this we can say that 7√5 is irrational number.

Hope this helps...

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