prove that7✓5 is an irrational number.
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5
Let 7√5 be rational.
So,
7√5 =
where p and q are coprimes and integers and q is not equal to 0.
√5 = p/7q
RHS is rational but LHS is irrational.
Rational cannot be equal to irrational.
Hence, assumption is contradicted.
7√5 is irrational.
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Answered by
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Answer:
Let 7√5 be a rational number.
So,
7√5 = p/q.
(p and q are co-prime number and q ≠ 0)
=> √5 = p/7q
As, we can see that p/7q ia rational so √5 should also be rational. But this contradict the fact that √5 is irrational.
So, by this we can say that 7√5 is irrational number.
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