Question

prove thatb(x+y)(x-y)+(y+z)(y-z)+(z+x)(z-x)=0​

Answer 1

They are in brackets
Brackets mean 0
And is 0

Answer 2

Answer:

Here :

Step-by-step explanation:

So, (x+y)(x-y)+(y+z)(y-z)+(z+x)(z-x)

= x^2 - y^2 + y^2 - z^2 + z^2 - x^2

= 0

Its quite simple. I hope this helps.