Question

Prove the
(1) (AB) C = (AC) B = A (
BC) -
-CABA​

Answer 1

Answer:

True take (A +B)*(A’ + C) and expand

(A+B) * (A'+C) = AA’ +AC + A’B + BC

However AA’ = 0, so

(A+B) * (A'+C) = AC+A'B + BC

Let’s evaluate these output terms

if A is true and B is false, A’ is false again the output can only be true is if C is true

AC is a necessary term in the output

If B is true and A is false, A’ is true and the output is true, so A’B is another needed term

What about BC, set them both true in ( A +B)(A’ + C)

( A +1)(A’ +1) note if A is high AC is true and BC is not needed

But if A is false A’ is true and A’B is true and again BC is not needed

Answer 2

Answer:

Prove the

(1) (AB) C = (AC) B = A (

BC) -

-CABA

Step-by-step explanation:

Prove the

(1) (AB) C = (AC) B = A (

BC) -

-CABA