Math, asked by shrutiwankhade17, 2 months ago

prove the (1+w²)³=-1 ​

Answers

Answered by senboni123456
4

Step-by-step explanation:

We have,

 \rm(1 +  \omega^{2} )^{3}

We know,  1+\omega+{\omega}^{2}=0

so,1+{\omega}^{2}=-\omega

Now,

 \rm = (1 +  \omega^{2} )^{3}

 \rm = ( -   \omega )^{3}

 \rm = -   (\omega )^{3}

 \rm = -   1

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