prove the a cyclic parllelogram
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Given ABCD is a parallelogram so
angle A = angle B ..........1
ABCD is a cyclic quadrilateral so
Angle A + Angle B = 180 degree ........2
Angle A + Angle A = 180 degree ( A=B from 1)
2 angle A= 180 degree
Angle A = 180/2 = 90 degree.
As ABCD is a parallelogram (given) in which each angle is 90 degree (provrd above) and we know a parallelogram in which one angle is 90 then it is a rectangle.
Hence, ABCD is a parallelogram.
angle A = angle B ..........1
ABCD is a cyclic quadrilateral so
Angle A + Angle B = 180 degree ........2
Angle A + Angle A = 180 degree ( A=B from 1)
2 angle A= 180 degree
Angle A = 180/2 = 90 degree.
As ABCD is a parallelogram (given) in which each angle is 90 degree (provrd above) and we know a parallelogram in which one angle is 90 then it is a rectangle.
Hence, ABCD is a parallelogram.
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