prove the above axiom
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Solution
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Solution
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Step-by-step explanation:
l₁ and l₂ are two parallel lines and m is the transversal.
Here, Exterior angles are ∠1, ∠2, ∠7 and ∠8
Interior angles are ∠3, ∠4, ∠5 and ∠6
Corresponding angles are
- ∠1 and ∠5
- ∠2 and ∠6
- ∠4 and ∠8
- ∠3 and ∠7
Thus, (i) ∠1 = ∠5, (ii) ∠2 = ∠6, (iii) ∠4 = ∠8 and (iv) ∠3 = ∠7
If a transversal intersects two parallel lines then each pair of alternate interior and exterior angles are equal.
(a) ∠1 = ∠7
Also, (b) ∠1 = ∠3,
Because they are vertically opposite angles.
From (a) and (b),
∠1 = ∠7 and ∠1 = ∠3
⇒∠7 = ∠3
But, ∠7 and ∠3 corresponding angles.
This can be proved for all sets of corresponding angles.
So, if a transversal intersects two lines such that a pair of corresponding angles is equal, then the two lines are parallel to each other.
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