Question

prove the above identity​

Answer 1

Step-by-step explanation:

sec ^6 = (sec^2) ^3

sec ^2 = 1+ tan^2 so

( 1+ tan ^2) ^3

1+ (tan^2) ^3 + 3*1*tan^2 ( 1+ tan^2)

1 + tan ^6 + 3*tan ^2 *sec ^2

using identity ( a+b) ^ 3 = a^3 + b ^3 + 3ab ( a+bk