Math, asked by Anonymous, 3 months ago

Prove the above , if provided that the given limit is a real number .✓

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Answered by abirrpr24
0

Answer: 87/228

Step-by-step explanation:

Q.5/3 × 1/2 - 5/6 × 2/10 + (-6/2×3/2)

= 5/3 × 1/2 - 5/6 × 2/10 + (-6/2×3/2)

= 5/6 - 5/6 × 2/19 + (-6/2×3/2)

= 5/6 - 10/38 + (-6/2×3/2)

= 5/6 - 10/38 - 18/4

= 5/6 - [{(20-19)/76}]

= 5/6 - 1/76

= (90 - 3)/228

= 87/288

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