Question

prove the above mentioned sum

Answer 1

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L.H.S =(secθ – 1)/ (sec θ + 1)

(1/cosθ - 1)/ (1/cos θ +1)

(1 – cosθ/cosA)/ (1 + cosθ/cosθ)

(1 – cosθ)/ (1 + cosθ)

Multiplying the  numerator and denominator by (1 + cosθ), we get

(1 - cosθ)(1 + cosθ)/ (1 + cosθ)²

(1 – cos²θ)/ (1 + cosθ)²

sin²θ/ (1 + cosθ)²

↔ [ sinA/(1 + cosA) ]²

= R.H.S

HENCE POVED !

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