prove the above que with appropriate proof.
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Heya User,
--> ∠ AEY = 90° [ XY is tangent ]
--> ∠ ACE = 90° [ Angle subtended by diameter ] --> ( i )
--> ∠ YAE = ∠ EAC [ common angle ] --> ( ii )
Plz just mark AE ∩ BC = R.
Now, from ( i ) and ( ii ) -->
---> ΔACE ~ ΔAEY [ AA ]
--> AC / AE = AE / AY
--> AC * AY = AE² ------> ( i )
Similarly, ΔABE ~ ΔAEX [ AA ]
--> AB / AE = AE / AX
=> AB . AX = AE² -------> ( ii )
From ( i ) and ( ii ) -->
---> AC . AY = AB . AX √√ Proved...
--> ∠ AEY = 90° [ XY is tangent ]
--> ∠ ACE = 90° [ Angle subtended by diameter ] --> ( i )
--> ∠ YAE = ∠ EAC [ common angle ] --> ( ii )
Plz just mark AE ∩ BC = R.
Now, from ( i ) and ( ii ) -->
---> ΔACE ~ ΔAEY [ AA ]
--> AC / AE = AE / AY
--> AC * AY = AE² ------> ( i )
Similarly, ΔABE ~ ΔAEX [ AA ]
--> AB / AE = AE / AX
=> AB . AX = AE² -------> ( ii )
From ( i ) and ( ii ) -->
---> AC . AY = AB . AX √√ Proved...
1sahim:
thank you very very much
ans this one : From the same place at 7am 'A' started walking in north at the speed of 4 km/hr. After 1 hour B started cycling in the east at the speed of 8 km/hr. At what time will they be at a distance of 20 km apart from each other????
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