Question

prove the above question​

Answer 1

Answer:

suppose that theta is equal to alfa

$l.h.s = \frac{ \tan(90 - \alpha ) }{ {cosec}^{2}( \alpha ) \tan( \alpha ) } = \frac{ \cot( \alpha ) }{ {cosec}^{2} \alpha \: \tan( \alpha ) } \\ \\ = \frac{ \frac{ \cos( \alpha ) }{ \sin( \alpha ) } }{ \frac{1}{ {sin}^{2} \alpha } \times \frac{sin \alpha }{cos \alpha } } = {cos}^{2} \alpha$

Hence proved

Answer 2

Step-by-step explanation:

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