Question

prove the above statement...

Answer 1

Hii There!!!


Here firstly consider L.H.S

=> sin(90°-theta) × cos(90°- theta)

= cos theta × sin theta

= sin theta × cos theta


Now if we consider R.H.S we get,

=> tan theta / 1 + tan^2 theta

= tan theta / sec^2 theta

= (sin theta / cos theta) × cos^2 theta

= sin theta × cos theta


Hence , L.H.S = R.H.S



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Hope it helps✌