Question

Prove the above trigonometric equation​

Answer 1

Answer:sin^2 A= 1-cos^2 A

LHS

Sin^2A/cosA +cos^2A/cosA

1-cos^2A+cos^2A/cosA

1/cosA = sec A

Step-by-step explanation:For the convenience of typing, let us take theta= A.

Answer 2

Hi mate.

Simple bro first know about trignometry basic formulas sin ^2 A + cos^2 A= 1.

And 1/cosA = sec A now come to question,first solve LHS. LHS= (sin^2 theta/ cos theta )+

Cos theta [ take LCM]

=( sin^2 theta+ cos^2 theta/ cos

theta).

= 1/ cos theta= sec theta = RHS. I hope it help you✌️