Math, asked by ashoktiwari8148, 3 months ago

prove the above trigonometric relation .​

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Answered by Anonymous
73

Answer:

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Refer to attachment for 100% wrong answer.

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Answered by PriyaGsis
1

Answer:

LHS :(sin^{4}  \theta- cos^{4}\theta + 1 ) cosec^{2} \theta

( ( sin^{2}\theta)^{2}  - ( cos^{2}\theta)^{2}  + 1) cosec^{2} \theta

( (sin^{2} \theta - cos^{2} \theta) ( sin^{2} \theta + cos^{2} \theta) +1 ) cosec^{2} \theta

( ( sin^{2} \theta - cos^{2} \theta) (1)  + 1) cosec^{2} \theta

[((sin^{2} \theta - (1- sin^{2} \theta)) +1] cosec^{2} \theta

(sin^{2} \theta - 1 + sin^{2} \theta +1) cosec^{2} \theta

(2sin^{2} \theta)cosec^{2} \theta

(\frac{2sin^{2}\theta }{1} ) ( \frac{1}{sin^{2} \theta} )

⇒2 = R.H.S

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