Prove the above trigonometry problem
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just convert it into sine and cos
it becomes
(sec^2 a / cosec^2a)=tan^2a.....(1 proved)
Now middle one becomes
[(cosa-sina/cosa)/(sina-cosa/sina)]^2=[-tana]^2
=tan^2a..........proved
it becomes
(sec^2 a / cosec^2a)=tan^2a.....(1 proved)
Now middle one becomes
[(cosa-sina/cosa)/(sina-cosa/sina)]^2=[-tana]^2
=tan^2a..........proved
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