prove the altitude of a triangle are concurrent
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Let a b c a ¯ , b ¯ , c be the position vectors of the points A, B, C respectively. ∴ CR is also the altitude of ∆ABC. . ∴ All three altitudes of ∆ABC intersect at a common point. Thus, the altitudes of a triangle are concurrent.
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Let a b c a ¯ , b ¯ , c be the position vectors of the points A, B, C respectively. ∴ CR is also the altitude of ∆ABC. . ∴ All three altitudes of ∆ABC intersect at a common point. Thus, the altitudes of a triangle are concurrent.
Step-by-step explanation:
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