Question

Prove the diagonal of a parallelogram bisected each other.

Answer 1

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$\tt\large{\red{Correct \: Question:-}}$

Prove that the diagonal of a parallelogram bisect each other.

$\tt\large{\red{Answer:-}}$

$\tt\large{\green{Given:-}}$

$\sf\ ||gm ABCD \: in \: which\: diagonals \: AC \: and \: BD\: bisect \: each \: other.$

$\tt\large{\purple{To \: Prove:-}}$

$\sf\ OA = OC \: and \: OB = OD$

$\tt\large{\purple{Proof:-}}$

$\sf\ AB || CD \: (Given)$

$\sf\ ∠1 = ∠2 \: (alternate ∠s)$

$\sf\ ∠3 = ∠4 \: (alternate ∠s)$

$\sf\ and \: AB = CD \: (opposite \: sides \: of //gm)$

$\sf\ COD = AOB \: (A.S.A. rule)$

$\sf\ OA = OC \: and \: OB = OD$

$\sf\ Hence \: the\: result$ !!

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