prove the equation of motion by graphical method
v² = v²+2a s
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hey mate your answer is here ⬇️⬇️⬇️⬇️⬇️
Graph for derivation
we know : displacement = area under the velocity time graph .
S= area of trapezium ACEF
S= 1/2 ( b¹ + b² ) h
s= 1/2 ( AF+CE )FE
S= 1/2 ( U+ V) T
We know -v= u+ at
v-u/a= t
now 2 in 1
S= 1/2( v+u) (v-u)
2as= ( v+u) (v-u)
2as=v²-u²
[v² - u2 = 2as]
hope it will help u
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Explanation:
sbse phli bat V2 = V2 + 2as nhi hota ..........V2= u2+2as hota h.
jo pages mne share kiye h usm tino derevation h with graph 1st k bina dusri nhi ho skti.......isliye pure pages bheje h...
2nd page p mark kr diya h us derivation k bare m jo puchi gyi h ...
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