Physics, asked by vivekanu1999p96btz, 1 year ago

Prove the first equation of motion graphically

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Answered by Kenta11
3
I think this will help you
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Answered by nehatigga801
5
Initial velocity of the body=u=OA, final velocity=v=BC ,but from the graph BC=BD+BC. Therefore v=BD+BC. Again DC=OA. So. V=BD+OA. From equation (1)OA=u and v=BD+U. We should find out the value of BD now. We know that the slope of a velocity-time graph is equal to (a)acceleration. Thus, a=BD/AD. But AD=OC=t ,so putting t in place ofAD in the above relation ,we get: a=BD/t .Now ,putting the value ofBD in equation(4) we get:v=at+u. Therefore v=u+at.
Hence,derived.

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