prove the following
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Theta is written as @
Tan@/tan(90-@) +sin(90-@)/cos@=sec²@
Tan@/cot@ + Cos@/cos@=sec²@
{As cot@=1/tan@}
Tan²@+1=sec²@
Sec²@=sec²@
I hope this much will help you
Tan@/tan(90-@) +sin(90-@)/cos@=sec²@
Tan@/cot@ + Cos@/cos@=sec²@
{As cot@=1/tan@}
Tan²@+1=sec²@
Sec²@=sec²@
I hope this much will help you
Answered by
1
I hope it will help you.
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