Question

prove the following​

Answer 1

Answer:

$sin(\pi + x) = - sinx \\ sec(\pi - x) = - secx \\ tan(2\pi - x) = tanx \\ cos( \frac{\pi}{2} + x) = - sinx \\ sin(\pi - x) = sinx \\ \\ so \: given \: can \: be \: rewritten \: as \\ \frac{( - {sin}^{3}x) {sec}^{2}x( - tanx) }{ {sin}^{2} x \: sinx \: {cosec}^{2} x} \\ { - tan}^{3} x \\ hence \: proved$

Answer 2

Answer:

this is correct...........................