Question

Prove the following ​

Answer 1

Answer:

Step-by-step explanation:

cos²Ф (1+ tan²Ф ) = cos²Ф (sec²Ф) = cos²Ф ×1/cos²Ф = 1

Answer 2

On taking L. H. S. :

${ \cos }^{2} \alpha (1 + { \tan }^{2} \alpha ) \\ \\ = > { \cos}^{2} \alpha . { \sec }^{2} \alpha \\ \\ = > { \cos }^{2} \alpha . \frac{1}{ { \cos }^{2} \alpha } = 1$

HENCE PROVED ✔✔

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