Question

Prove the following
(6a-5b)^2 - ( 6a+5b)^2/ab= -120

Answer 1

Answer:

PROVED

Step-by-step explanation:

LHS=36a^2+25b^2-60ab-(36a^2+25b^2+60ab)/ab

=36a^2+25b^2-60ab-36a^2-25b^2-60ab/ab

=-60ab-60ab/2

=ab(-60-60)/ab

ab from numerator and denomenator gets cancelled. so,

=-60

Answer 2

Step-by-step explanation:

LHS=(6a-5b)^2-(6a+5b)^2/ab

=(6a)^2-2×6a×5b+(5b)^2-{(6a)^2+2×6a×5b+(5b)^2/ab

=(36a^2-60ab+25b^2)-(36a^2+60ab+25b^2)/ab

=36a^2-60ab+25b^2-36a^2-60ab-25b^2/ab

=-120ab/2=-120 =RHS "HP"