Question

.Prove the following are irrational i) 3÷2√3​

Answer 1

Answer:

3+√2 = a/b ,where a and b are integers and b is not equal to zero .. therefore, √2 = (3b - a)/b is rational as a, b and 3 are integers.. But this contradicts the fact that √2 is irrational.. So, it concludes that 3+√2 is irrational

Answer 2

let 3÷2√3 be a rational number

3÷2√3 = r ( rational )

2√3. = r×3

√3. = r × 3 /2

r × 3/2 is a rational number but √3 is an irrational number. so this contradicts that 3÷2√3 is an irrational number.

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