Prove the following cos (sin inverse 3/5 +cot inverse 3/2)=6/5√13
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sinA=3\5 cotB=3\2
cos (A+B)=4\5×3\root13-3/5×2/root13
6/5root13
cos (A+B)=4\5×3\root13-3/5×2/root13
6/5root13
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6/5root13
Is the answer
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