Math, asked by shwetha25, 1 year ago

Prove the following

cos6x =32cos^6 x -48cos^4 x + 18cos^2 x -1.

Answers

Answered by siddhishukla123
18
I hope this is correct and if it helped you please mark it brainliest
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shwetha25: thank u
thriveni6: Tq
Answered by sandy1816
1

\large \: cos6x \\  \\  = cos3.2x \\  \\  = 4 {cos}^{3} 2x - 3cos2x \\  \\  = 4(2 {cos}^{2} x - 1) ^{3}  - 3(2 {cos}^{2} x - 1) \\  \\  = 4(8 {cos}^{6} x - 12 {cos}^{4} x + 6 {cos}^{2} x - 1) - (6 {cos}^{2} x - 3) \\  \\  = 32 {cos}^{6} x - 48 {cos}^{4} x + 24 {cos}^{2} x - 4 - 6 {cos}^{2} x + 3 \\  \\  = 32 {cos}^{6} x - 48 {cos}^{4} x + 18 {cos}^{2} x - 1

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