Prove the following :- (i) 3^log4 = 4^log3
(ii) 27^log2 = 8^log3
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Answer:
(i)3^log4=4^log3
3^log4
=>log4 = 3
log=3/4
4^log 3
=> log 3 = 4
log=4/3
log3/4 = log4/3
cutting the both log we will get 3/4 = 4/3
(11) 27^log 2
=> log2=27
log=27/2
8^log3
=> log 3=8
log=8/3
log27/2 = Iog8/3
cutting the two log
we will get 27/2 = 81 / 3
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