Prove the following :-
(i) (sec A + tan A) (1 - sin A) = cos A
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Step-by-step explanation:
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Step-by-step explanation:
LHS => (secA+tanA)(1−sinA)
=( 1 / cosA + sin A /cos A ) (1−sinA)
=( 1+sinA /cos A) (1−sinA)
= (1+sinA)(1−sinA) / cos A
= (1−sin² A) / cos A
= cos² A / cos A => cos A
∴(secA+ tanA) (1− sinA) => cosA
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