Math, asked by sabitasethi70, 4 months ago

Prove the following
(i) sin A. sin (B-C) + sin B sin (C-A)
+ sin C. sin(A - B) = 0
(ii) cos A. sin (B-C) + sin B sin (C-A
+ cos C. sin(A - B) = 0
sin (B-C)
(iii) sin B. sin
+
+
= 0
sin(C-A) sin(A-B)
sin C. sin A sin A.sin B
(iv) tan’A - tan’B
sin (A + B). sin(A-B)
cos2 B
2​

Answers

Answered by ayisha12345anwar
1

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I didn't understand your question clearly

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