Prove the following identities :
1. (sin 0 + cosec 0)2 = sin20 + cosec2 0 + 2.
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Step-by-step explanation:
To Prove:(sin 0+cosec 0)2=sin20+cosec20+2
LHS-
(sin 0+ cosec 0)2
we know that,
(a+b)2=a2 + b2 +2ab
therefore,
(sin 0+ cosec 0)2
= sin20 + cosec20 + 2{sin 0(cosec 0)} ______________ 1
since,
cosec 0=1/sin 0
putting value of cosec 0 in 2{sin 0(cosec 0)} of eq.1.We get,
sin20 + cosec20 + {2(sin 0 *1/sin 0)}
=sin20 + cosec20 +2
=RHS
Hence,proved
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