Math, asked by swati5728, 1 year ago

Prove the following identities :
1. (sin 0 + cosec 0)2 = sin20 + cosec2 0 + 2.​

Answers

Answered by AtinGR8
2

Step-by-step explanation:

To Prove:(sin 0+cosec 0)2=sin20+cosec20+2

LHS-

(sin 0+ cosec 0)2

we know that,

(a+b)2=a2 + b2 +2ab

therefore,

(sin 0+ cosec 0)2

= sin20 + cosec20 + 2{sin 0(cosec 0)} ______________ 1

since,

cosec 0=1/sin 0

putting value of cosec 0 in 2{sin 0(cosec 0)} of eq.1.We get,

sin20 + cosec20 + {2(sin 0 *1/sin 0)}

=sin20 + cosec20 +2

=RHS

Hence,proved


AtinGR8: Please check it sis. Is it right or not
swati5728: right bro
swati5728: thanks
AtinGR8: please sis answer my question too
Answered by kashish1439
4

Answer:

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Step-by-step explanation:

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