Prove the following identities: √1+sinθ/√1-sinθ + : √1-sinθ/√1+sinθ = 2secθ
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√1+sinθ/√1-sinθ+√1-sinθ√1+sinθ
=(√1+sinθ)²+(√1-sinθ)²/√1-sin²θ
=1+sinθ+1-sinθ/√cos²θ
=2/cosθ
=2secθ
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