Prove the following identities: √1-sinθ/√1+sinθ = secθ - tanθ
Answers
Answered by
0
Step-by-step explanation:
√1-sinθ/√1+sinθ
=√(1-sinθ)²/1-sin²θ
=√(1-sinθ)²/cos²θ
=(1-sinθ)/cosθ
=secθ-tanθ
Similar questions