prove the following identities:
(1 + tanA)² + 1- tanA)²= 2sec²A
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Step-by-step explanation:
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Step-by-step explanation:
Take left hand side of the equation (1+tanA)
2
+(1−tanA)
2
=2sec
2
A.
LHS = (1+tanA)
2
+(1−tanA)
2
=1+tan
2
A+2tanA+1+tan
2
A−2tanA
=2+2tan
2
A
=2(1+tan
2
A)
=2sec
2
A
=RHS
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